Question

Construct a quadrilateral PQRS where PQ = 4 cm,QR = 6 cm, RS = 5 cm, PS = 5.5 cm and PR = 7 cm.[3 MARKS]

Answer 1

Steps of constructions : 1 Mark
Construction : 2 Marks

Steps of construction:

1. Construct $\Delta PRS$ using SSS construction condition, where RS = 5 cm, PS = 5.5 cm and PR = 7 cm.
2. Now, we have to locate the fourth point Q. This ‘Q’would be on the side opposite to S with reference to PR.
3. With P as centre, draw an arc of radius length 4 cm. i.e, PQ = 4 cm.
4. With R as centre, draw an arc of radius 6 cm. i.e, QR = 6 cm.
5. The point of intersection of these two arcs is Q.
6. Join PQ and RQ to complete PQRS. PQRS is the required quadrilateral.