Question

Construct a quadrilateral $PQRS$, with $PQ=3$ cm, $QR=9$ cm, $RS=5$ cm, $\angle Q={45}^{\circ },\angle R={60}^{\circ }$

Answer 1

First draw a line segment $QR=9$ cm.

Make $\angle Q={45}^0$ at point Q and $\angle C={60}^0$ at point $R$.

Open compass $3$ cm and mark curve at angle line from point $Q$ this cut at point $P$.

After open compass $5$ cm and mark curve at angle line from point $R$ this cut at point $S$.

Join $P$ and $S$.

Hence, $PQRS$ is required quadrilateral.