Question

Construct a quadrilateral $PQRS$ with $PQ=4.7cm,QR=3.9cm,\angle QPS={75}^o,\angle PQR={120}^o$ and $\angle QRS={105}^o$. Measure $\angle PSR$.

Answer 1

$\Rightarrow$ Draw a line segment $PQ=4.7cm$

$\Rightarrow$ Take $P$ and $Q$ as a center and draw an angle of ${75}^o$ and ${120}^o.$

$\Rightarrow$ Cut off $QR=3.9cm$

$\Rightarrow$ Take $R$ as a center and draw an angle of ${105}^o,$ which meet angle $P$ at point $S.$

$\Rightarrow$ Now, measure $\angle PSR$

$\Rightarrow$ We get, $\angle PSR={60}^o.$