Construct a quadrilateral QRST in which angle Q =50° , angle R =70°, angle S =130°,QR=8cm , QT=5.8cm.

Open in App

Solution

her this can constructed by following steps
1. draw the line QR=8cm

2. draw angle 70° from R as base QR and extend the line

3. draw the angle 50° from the point Q as base QR and extend the line
4. find a point in which we get 5.8 cm as QT

5. find the angle T
ie, <T=360°-(50°+70° +130°)
. =110°

6. draw the angle T to the line SR so that we get a point S
the angle S automatically will be 130°

Suggest Corrections

Similar questions

Construct a quadrilateral PQRS in which PQ =4 cm, QR=5 cm, $∠ P = 50^{\circ}, ∠ Q = 110^{\circ}$ and $∠ R = 70^{\circ}$

∆

∠

70^{°}

∠

80^{°}

We cannot construct a quadrilateral PQRS with PQ =6cm, QR = 5 cm, ∠P = 70^o, ∠Q = 150^o and the measurement of ∠R as

Construct right angle triangle PQR in which ∠Q = 90°, QR = 4.5 cm and ∠R = 50°.

△

P Q R

∠

70^{o}

∠ R = 70^{o}

P Q + Q R + R P

= 10

Join BYJU'S Learning Program