Construct a rectangle ABCD, when:
Diagonal $A c = 6.3$ cm, and diagonal $B D = 5.8$ cm.

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Solution

A rhombus has diagonals perpendicular to each other.
1. Draw $A C = 6.3 c m$
2. Draw perpendicular bisector XY of AC intersecting AC at O.
3. Taking O as centre and $\frac{1}{2} \times 5.8 = 2.9 c m$ as radius
draw two arcs intersecting OX and OY at B and D respectively.
4. Join AB, BC, CD and AD.

ABCD is the required rhombus.

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Similar questions

A B = 5.8 c m

A C = 8.2

B D = 6.2 c m .

Construct a rhombus ABCD, if ;

(i) AB = 4 cm and $∠ B = 120^{\circ}$ .

(ii) BC = 4.7 cm and $∠ B = 75^{\circ}$

(iii) CD = 5 cm and diagonal BD = 8.5 cm.

(iv) BC = 4.8 cm, and diagonal AC = 7 cm.

(v) diagonal AC = 6 cm and diagonal BD = 5.8 cm.

(vi) diagonal AC = 4.9 cm and diagonal BD = 6 cm.

(vii) diagonal AC = 6.6 cm and diagonal BD = 5.3 cm.

A B C D

A C = 6.3 c m

B D = 7 c m

45^{\circ}

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