Question

Construct a rectangle $PQRS$, when $PQ=5.5cm$ and the diagonals $QS=5.2cm$.

Answer 1

Step of construction

(i) Draw PQ = 5.5 cm

(ii) Make angle $\angle QPX={45}^{\circ }$

(iii) Cut PR = 5.2 at PX

(iv) Draw angle ${90}^{\circ }$ at P

(v) Cut PS = 5.5 at PY

(vi) Draw $\angle R={90}^{\circ }$ which meets at Q.

Here error

Diagonal can not be less than any side

and here, side = 5.5

d = 5.2