Question

Construct a Rhombus $PQRS$ such that $PR=8$ cm, $QS=5.4$ cm.

Answer 1

Given : $PR=8$cm and $QS=5.4$cm
We know that,All sides of rhombus is equal and Diagonals bisect each other at right angles.
So,$PA=AR=4$ cm and $QA=AS=2.7$cm
To construct rhombus, we follow these steps—
Step $1)$ Draw a line $QS=5.4$ cm
Step $2)$ Now take radius of $2.7$ cm and bisect the line $QS$. Midpoint of line $QS$ is $A$.
Step $3)$ Construct a right angle on point $A$ and extend into both directions. Now take radius of $4$ cm and draw two arc on both side , by taking center $A$ . we will get two points $P$ and $R$.

Step $4)$ Now join $PQ,PS,SR$ and $QR$.

Result:$PQRS$ is the required rhombus.