Question

Construct a right angle $△ABC$, right angled at $B$, when hypotenuse $CA=8cm$ and $AB=BC$.

Answer 1

Let $AB=BC=a$
Since $ABC$ is a right angled triangle ,

$\therefore \sqrt{a^2+a^2}=8.0$

$\Rightarrow \sqrt{2}a=8.0$

$\Rightarrow a=5.6cm$
1. Draw the base side $BC=5.6cm$

2. At point $B$, draw an angle of ${90}^{\circ }$

3. At point $C$, draw an arc of $AC=8.0cm$ intersecting the arm of the angle ${90}^{\circ }$ and the arc drawn in step 2

4. Name the point of intersection, as $A$

5. $ABC$ is the required triangle.