Construct a right angle triangle ABC such as $A C = 5 c m, B C = 3 c m$ , $∠ B = 90^{o}$
What would be the length of $A B$ after construction?

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Solution

The correct option is C $4$ cm
In triangle in $△ A B C$ , by Pythagoras theorem

$A C^{2} = A B^{2} + A C^{2}$

Given, $A B = 5 c m, B C = x$

$5^{2} = x^{2} + 3^{2}$

$x^{2} = 5^{2} - 3^{2} = 25 - 9 = 16$

$x = \sqrt{16} = 4 c m$
Hence, $A B = 4$ cm.

Or
Simply after constructing, we can measure AB side.

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$△$ ABC is constructed such that AB = 7 cm, AC = 4 cm and $∠$ A = 75 $^{\circ}$ . Then the length of side BC is _____ .

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A C = 4 c m

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