Question

Construct a right angle $△PQR$, where $PQ=QR$, and hypotenuse $PR=8$ units. Also, find the length of $PQ$ of $△PQR$.

• A. $5.65$
• B. $4.5$
• C. $6.3$
• D. $7$

Answer 1

Answer: (A)

$5.65$

In triangle in $△PQR$, by Pythagoras theorem

$P{R}^2=P{Q}^2+Q{R}^2$

Given, $PQ=QR=x$

$P{R}^2=2P{Q}^2$

$x^2=\frac{64}{2}=32$

$x=\sqrt{32}=5.656units$