Construct a square of side $5 c m .$ Then the area of half of the constructed square (in $c m^{2}$ ) is :

12.5 c m^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

25 c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50 c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6.75 c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $12.5 c m^{2}$
Required area $= \frac{25}{2} = 12.5 c m^{2}$

Suggest Corrections

Similar questions

Q. Construct a square of side

5 c m

. Find its area also

Refer to the following figure. Three squares are constructed on each side of the triangle as shown, with the length of each square equal to the side of the triangle on which it is constructed. The angle opposite to the blue colour square is the right angle. If the largest side 5 cm, then find the sum of the area of the yellow square and brown square.

Q. Area of a square of side 5 cm is

Q. Construct a square whose diagonal is

5 c m

in length. Then the length of the side of the square is:

Construct a square of side

5 c m .

Then measure of the angle made by the diagonals is:

Join BYJU'S Learning Program

Construct a square of side 5 cm. Then the area of half of the constructed square (in cm2) is :

The correct option is A 12.5cm2Required area =252=12.5cm2

Construct a square of side $5 c m .$ Then the area of half of the constructed square (in $c m^{2}$ ) is :

The correct option is A $12.5 c m^{2}$
Required area $= \frac{25}{2} = 12.5 c m^{2}$