Construct a trapezium ABCD, when :
AB = $4.8$ cm, BC = $6.8$ , CD = $5.4$ cm, angle B = $60^{\circ}$ and AD || BC.

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Solution

Steps :
(i) Draw BC = $6.8$ cm.
(ii) With B as a centre and radii $4.8$ cm draw an are at A such that $∠ B = 60^{\circ}$ .
(iii) From point A draw a line AP such that AP || BC.
(iv) With C as a centre and radii $5.4$ cm draw an are at D on the line AP.
(v) Now join AB CD
ABCD is the required trapezium.

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Construct a quadrliateral ABCD; if:

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