Question

Construct a trapezium ABCD with dimesions: $AB=6cm,AD=4cm,CD=3cm$, $\angle DAB={90}^o$, and $AB\parallel CD$. Find the value of $\angle BCD$ (in degrees).

• A. $127$
• B. $107$
• C. $160$
• D. None of these

Answer 1

The correct option is A $127$

$\Rightarrow$ Draw a line segment $AB=6cm$

$\Rightarrow$ Construct an angle of ${90}^{\circ }$ at point $A$.

$\Rightarrow$ Cut off $AD=4cm$

$\Rightarrow$ Draw a horizontal line through a point $D$.

$\Rightarrow$ Cut off that line $CD=3cm$

$\Rightarrow$ Join $BC$.

$\Rightarrow$ Thus, $ABCD$ is the required trapezium.

$\Rightarrow$ We have to measure $\angle BCD$.

$\Rightarrow$ $m\angle BCD={127}^{\circ }$