Construct a trapezium $R I S K$ in which $R I ∥ K S$ , $R I = 7 c m, I S = 5 c m, R K = 6.5 c m$ and $∠ I = 60^{\circ}$ .

Open in App

Solution

$∠ I + ∠ S = 180^{\circ}$
$60^{\circ} + ∠ S = 180^{\circ}$ [co-interior angles]
$∠ S = 120^{\circ}$

Steps of Construction
Step I: Draw an arc $R I$ = 7 cm.
Step II: Make $∠ R I X = 60^{\circ}$ .
Step III: With $I$ as centre and radius 5 cm, draw an arc, cutting $I X$ at $S$ .
Step IV: Make $∠ I S Y = 120^{\circ}$ .
Step V: With $R$ as centre and radius 6.5 cm, draw an arc cutting $S Y$ at $K$ .
Step VI: Join $K R$ .

Thus, $R I S K$ is the required trapezium.

Suggest Corrections

Similar questions

R I ∥ K S

∠ I = 60^{\circ}

Draw a trapezium ABCD in which AB || DC, AB = 7 cm, BC = 5 cm, AD = 6.5 cm and $∠ B = 60^{\circ}$

R I S E

R I = 4 c m, S E = 4.9 c m

R S = 7.2 c m

Construct a trapezium ABCD in which AB || CD, AB=6.8cm BC=5.2 cm AD=6.5cm and angle B=60°

∠

^{\circ}

∠

^{\circ}

Join BYJU'S Learning Program