Question

Construct a trapezium whose sides are given to be $10cm,4cm,6cm$ and $3cm$ such that the sides of length $10cm$ and $6cm$ are parallel. Then the measure of the base angles are:

• A. ${38}^{\circ },{83}^{\circ }$
• B. ${38}^{\circ },{68}^{\circ }$
• C. ${44}^{\circ },{83}^{\circ }$
• D. ${44}^{\circ },{68}^{\circ }$

Answer 1

Answer: (D)

${44}^{\circ },{68}^{\circ }$

Consider that $AB\parallel CD$

$\Rightarrow AB=10cm$ and $CD=6cm$

$AD=4m$ and $BC=3m$

$\therefore \angle DAB=44°$ and $\angle CBA=68°$

Hence, the answer is $44°,68°.$