Construct a $△ A B C, A B = 6 c m, B C = 7 c m$ and $∠ A = 60^{o}$ .

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Solution

$1.$ Draw a straight line $A B = 5.7$ cm
$2.$ Using Protractor from $A$ mark a point $∠ A = 60^{\circ}$
$3.$ Using compass of draw an arc of length $B C = 7$ cm
$4.$ Name the point of intersection of the arc of $7$ cm and the line making an angle with $A$ as $C$
Result: $△ A B C$ is the required triangle.

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Similar questions

△ A B C, A B = 6 c m, B C = 7 c m

∠ A = 60^{o}

△ A B C, A B = 6 c m, B C = 7 c m

∠ A = 60^{o}

A B C

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A B = 9 c m

A B C = 60^{o}

Δ A B C

A B = 5 c m, A C = 7 c m, B C = 6 c m

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