Construct a triangle $A B C$ , given the following
$A B = B C = 5.8 c m, B C = 5.8 c m$ and $A C = 4 c m$

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Solution

$1.$ Draw a straight line $A C = 4$ cm
$2.$ Using compass from $A$ draw an arc of length $5.8$ cm
$3.$ Using compass from $C$ draw an arc of length $5.8$ cm
$4.$ Name the point of intersection of both the arcs as $B$
$5.$ Join $A B$ and $B C$
Result: $△ A B C$ is the required triangle.

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A B C

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