Question

Construct a triangle ABC in which AB = 5.8cm,
BC + CA = 8.4 cm and $\angle B={60}^{\circ }$.

Answer 1

Steps of Construction

Step 1 : Draw AB = 5.8 cm

Step 2 : Draw ∠ABX = 60º

Step 3 : From point B, on ray BX, cut off line segment BD = BC + CA = 8.4 cm.

Step 4 : Join AD

Step 5 : Draw the perpendicular bisector of AD meeting BD at C.

Step 6 : Join AC to obtain the required triangle ABC