Question

Construct a $△ABC$ in which $AC=5cm$, and $\angle BAC={60}^{\circ }$ and $AB-BC=1.2cm$.

Answer 1

1. Draw a line $AC=5cm.$

2. Construct $\angle A={60}^{\circ }$ and mark it as $Y.$

3. Cut off line segment $AD=1.2cm$ on $AY$.

4. Join $C-D.$

5. Draw a perpendicular bisector of $CD$ such that it intersects $AY$ at $B$.

6. Join $B-C$.

7. $ABC$ is the required triangle.