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Question
Construct a triangle ABC, in which ∠B = 60°, ∠C = 45° and AB + BC+ CA = 22 cm.
Construct a triangle ABC, in which ∠B = 60°, ∠C = 45° and AB + BC+ CA = 22 cm.
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Solution
Steps-
-Draw line segment PQ of length 22 cm. From P draw ray PL which makes an angle 30 degree with PQ using a protractor. Similarly, draw ray QM which makes angle 90 degrees with PQ.
-Using angle bisector construction method, draw angle bisectors for angles APQ and angle AQP. Let these 2 angle bisectors meet at A.
-Using perpendicular bisector construction method draw perpendicular bisectors DE for AP and FG for AQ respectively.
-Let the point where DE meets PQ be B and let the point where FG meets PQ be C. Join AB and AC. The required triangle is triangle ABC.
Steps-
-Draw line segment PQ of length 22 cm. From P draw ray PL which makes an angle 30 degree with PQ using a protractor. Similarly, draw ray QM which makes angle 90 degrees with PQ.
-Using angle bisector construction method, draw angle bisectors for angles APQ and angle AQP. Let these 2 angle bisectors meet at A.
-Using perpendicular bisector construction method draw perpendicular bisectors DE for AP and FG for AQ respectively.
-Let the point where DE meets PQ be B and let the point where FG meets PQ be C. Join AB and AC. The required triangle is triangle ABC.
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