Question

Construct a $△ABC$ in which base $\angle B={60}^0$, height corresponding to base $BC=4.3$cm and length of median corresponding to side $AB=6$ cm.

Answer 1

$\left(i\right)$ Draw a line $BP$ of any suitable length.
$\left(ii\right)$ Construct $\angle DBP={60}^0$.
$\left(iii\right)$ Draw $MN$ parallel to $BP$ and at a distance of 43 cm from it i.e. $BE=4.3$ cm. Let $MN$ meets
$DB$ at point $A$.
$\left(iv\right)$ Joint $AB$ and by drawing its perpendicular
bisector, locate its mid-point $F$.
$\left(v\right)$ With $F$ as centre and radius equal to 6 cm
(length of given median), draw an arc which cuts $BP$ at point $C$.
$\left(vi\right)$ Join $A$ and $C$.
$△ABC$ is the required triange.