Question

Construct a $△$ $ABC$ in which base $BC=5.5cm,AB=6cm$ and $\angle ABC={120}^o$. Construct a circle circumscribing the triangle $ABC$.

Answer 1

Given $BC=5.5cm,AB=6cm$ and $\angle ABC={120}^o$

Step 1: Draw $BC$ of $5.5cm$. By using a protractor, mark $\angle B$ as ${120}^o$ and take $AB=6cm$. Join $AC$.

Step 2: Draw the bisection of sides $AB$ and $AC$. Join the points.

Step 3: Draw the circle with radius at the intersection point of the bisectors that passes through one of of the vertices.