Construct a triangle ABC in which BC = 4.5 cm, ∠B = 35° and difference between the other two sides is 2.8 cm. (Optional)

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Solution

The steps given below need to be followed to draw the required triangle

Step I: Draw a line segment BC of 4.5 cm length. At point B, make an angle measuring 35°, say ∠XBC.

Step II: Cut a line segment BD of 2.8 cm length (= AB − AC) on ray BX.

Step III: Join DC and draw the perpendicular bisector PQ of DC.

Step IV: Let it intersect BX at point A. Join AC. ΔABC is the required triangle.

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