Construct a triangle ABC in which BC -6 cm - - B -45- and AB - AC -2-5 cmSteps of construction-Step 1- Draw BC -6 cmStep 2- Construct - Y BC -45-Step 3 will beA- Join AC- - ABC is the required triangle-B- From ray BY- cut-off line segement BD -2-5 cmC- Draw perpendicular bisector of CD intersecting BY at A-D- Join CD

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Byju's Answer

Standard IX

Mathematics

Given Base(BC), Base Angle(ABC) and AB-AC

Construct a t...

Question

Construct a triangle ABC in which BC = 6 cm, $∠ B = 45^{\circ}$ and AB - AC = 2.5 cm

Steps of construction:
Step 1: Draw BC = 6 cm
Step 2: Construct $∠ Y B C = 45^{\circ}$
Step 3 will be -

Join AC,

Δ A B C

is the required triangle.

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Draw perpendicular bisector of CD intersecting BY at A.

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From ray BY, cut-off line segement BD = 2.5 cm

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Solution

The correct option is C From ray BY, cut-off line segement BD = 2.5 cm

Step 3: From ray BY, cut-off line segement BD = 2.5 cm. Join CD
Step 4: Draw perpendicular bisector of CD intersecting BY at A.
Step 5: Join AC, $Δ A B C$ is the required triangle.

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Construct a triangle ABC in which BC = 6 cm, ∠B=45∘ and AB - AC = 2.5 cm Steps of construction: Step 1: Draw BC = 6 cm Step 2: Construct ∠YBC=45∘ Step 3 will be -

The correct option is C From ray BY, cut-off line segement BD = 2.5 cm Step 3: From ray BY, cut-off line segement BD = 2.5 cm. Join CD Step 4: Draw perpendicular bisector of CD intersecting BY at A. Step 5: Join AC, ΔABC is the required triangle.

Construct a triangle ABC in which BC = 6 cm, $∠ B = 45^{\circ}$ and AB - AC = 2.5 cm

Steps of construction:
Step 1: Draw BC = 6 cm
Step 2: Construct $∠ Y B C = 45^{\circ}$
Step 3 will be -

The correct option is C From ray BY, cut-off line segement BD = 2.5 cm

Step 3: From ray BY, cut-off line segement BD = 2.5 cm. Join CD
Step 4: Draw perpendicular bisector of CD intersecting BY at A.
Step 5: Join AC, $Δ A B C$ is the required triangle.