Construct a triangle ABC in which BC - 6 cm- - B - 45- and AB - AC - 2-5 cm-Steps of construction-Step 1- Draw BC - 6 cm-Step 2- Construct -YBC - 45-Step 3 will be -

Step 3: From ray BY, cut off line segement BD = 2.5 cm. Step 4: nbsp;Join CD. Step 5: Draw perpendicular bisector of CD intersecting BY at A. Step 6: Join A ...

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Byju's Answer

Standard VII

Mathematics

Construction of Triangle When Two Sides and Included Angle is Given

Construct a t...

Question

Construct a triangle ABC in which BC = 6 cm, $∠ B = 45^{\circ}$ and AB - AC = 2.5 cm.

Steps of construction:
Step 1: Draw BC = 6 cm.
Step 2: Construct $∠ Y B C = 45^{\circ}$ .
Step 3 will be -

Join AC,

Δ A B C

is the required triangle.

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Draw perpendicular bisector of CD intersecting BY at A.

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From ray BY, cut-off line segement BD = 2.5 cm.

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Join CD.

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Solution

The correct option is C From ray BY, cut-off line segement BD = 2.5 cm.

Step 3: From ray BY, cut-off line segement BD = 2.5 cm.
Step 4: Join CD.
Step 5: Draw perpendicular bisector of CD intersecting BY at A.
Step 6: Join AC, $Δ A B C$ is the required triangle.

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Construct a triangle ABC in which BC = 6 cm, ∠B=45∘ and AB - AC = 2.5 cm. Steps of construction: Step 1: Draw BC = 6 cm. Step 2: Construct ∠YBC=45∘. Step 3 will be -

The correct option is C From ray BY, cut-off line segement BD = 2.5 cm. Step 3: From ray BY, cut-off line segement BD = 2.5 cm. Step 4: Join CD. Step 5: Draw perpendicular bisector of CD intersecting BY at A. Step 6: Join AC, ΔABC is the required triangle.

Construct a triangle ABC in which BC = 6 cm, $∠ B = 45^{\circ}$ and AB - AC = 2.5 cm.

Steps of construction:
Step 1: Draw BC = 6 cm.
Step 2: Construct $∠ Y B C = 45^{\circ}$ .
Step 3 will be -

The correct option is C From ray BY, cut-off line segement BD = 2.5 cm.

Step 3: From ray BY, cut-off line segement BD = 2.5 cm.
Step 4: Join CD.
Step 5: Draw perpendicular bisector of CD intersecting BY at A.
Step 6: Join AC, $Δ A B C$ is the required triangle.