Question

Construct a $△ABC$ in which $BC=7cm\angle B={75}^o$ & $AB+AC=13cm$.

Answer 1

Given that,

In $\Delta ABC$,

$BC=7cm,\angle B={75}^0\&AB+AC=13cm$.

Required: To construct the triangle $ABC$.

Then,

Draw the base $BC=7cm$.

At the point $B$ make an angle $XBC={75}^0$.

Cut a line segment $BD$ equal to $AB+AC=13cm$ from the ray $BX$.

Join $DC$.

Make an $\angle DCY=\angle BDC$.

lET $CY$ intersect $BX$ at $A$.

Hence,

$ABC$ is the required triangle.