Construct a triangle ABC in which BC = 7 cm, ∠B = 75° and AB + AC = 13 cm.

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Solution

The below given steps will be followed to construct the required triangle.

Step I: Draw a line segment BC of 7 cm. At point B, draw an angle of 75°, say ∠XBC.

Step II: Cut a line segment BD = 13 cm (that is equal to AB + AC) from the ray BX.

Step III: Join DC and make an angle DCY equal to ∠BDC.

Step IV: Let CY intersect BX at A. ΔABC is the required triangle.

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Similar questions

Construct a triangle ABC in which $B C = 7 c m, ∠ B = 75^{\circ} a n d A B + A C = 13 c m$

Construct a triangle $A B C$ in which $B C$ equal to $7 c m$ , Angle $B$ equal to $75$ degree and $A B + A C$ equal to $13 c m$ .

Construct a triangle ABC in which BC = 7cm, ∠B = 75° and AB + AC = 13 cm.

△ A B C

B C = 7 c m ∠ B = 75^{o}

A B + A C = 13 c m

Δ A B C

B C = 7 c m

∠ B = 75^{o}

A B + A C = 12.5 c m

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