Question

Construct a $△ABC$ in which BC = 8 CM, $\angle B={45}^{\circ }and\angle C={60}^{\circ }.$ Construct another triangle similar to $\Delta ABC$ such that its sides are $\frac{3}{5}$ of the corresponding sides of $\Delta ABC.$

Answer 1

1) Draw a line segment BC = 8 cm

2) Placing protractor at B draw a line ${45}^0$ to BC

3) placing protractor at C draw a line ${60}^0$ to BC

4) they meet at A . $△ABC$ is the required triangle .

Now for a similar triangle,length of the side corresponding to BC is $\frac{3}{5}$ $\times 8=4.8cm$

1) cut an arc of length 4.8cm on BC

2)let the point at which this arc meets BC be D

3) draw a line from D parallel to AC onto AB .It meets AB at E

Now $△DBE$ is the required triangle (since $\angle Biscommonand\angle C=\angle D$)