Question

Construct a triangle ABC in which BC = 8 cm, ∠B = 45° and AB − AC = 3.5 cm.

Answer 1

The below given steps will be followed to draw the required triangle.

Step I: Draw the line segment $BC=8cm$ and at point $B$, make an angle of $45°$, say $\angle XBC.$

Step II: Cut the line segment BD = 3.5 cm (equal to $AB-AC$) on ray $BX$.

Step III: Join $DC$ and draw the perpendicular bisector $PQ$ of $DC.$

Step IV: Let it intersect $BX$ at point $A$. Join $AC$

Hence, $\Delta ABC$ is the required triangle.