Question

Construct a triangle ABC in which BC is 3.5 cm, Angle B is ${75}^{\circ }$ and AB+AC=6.5cm [4 MARKS]

Answer 1

Steps : 1 Mark
Construction : 3 Marks

Steps:
1. Draw line segment BC of length 3.5 cm using ruler. At B construct an angle of measure ${75}^{\circ }$. Draw a ray BX.
2. Cut a line segment BD equal to AB+AC = 6.5 cm on ray BX.
3. Join CD.
4. Draw the perpendicular bisector of CD, intersecting BD at point A.
5. Join AC.
6. ABC is the required triangle.