Question

Construct a triangle ABC in which BC is 6 cm, $\angle B$ is ${70}^{\circ }$ and AB+AC=14cm by using method of perpendicular bisector. [4 Marks]

Answer 1

Steps : 1 Mark
Construction : 3 Marks

Steps:
1. Draw line segment BC of length 6 cm using ruler. From B using protractor, draw a ray BX which makes an angle of ${70}^{\circ }$ with BC.
2. Cut a line segment BD equal to AB+AC=14 cm from ray BX.
3. Join CD. Construct perpendicular bisector PQ for CD. Let PQ meet BD at A.
4. Join AC. Triangle ABC is the required triangle.