Construct a triangle ABC such that side BC - 3-8 m- -B - 45- and the sides AB - AC - 6-8 m-

Step 1: Construct the base BC = 3.8m Step 2: Construct an angle at B such that ∠B = 45°. Step 3: nbsp;Mark a point D on this ray such that BD = AB + AC. Ste ...

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Standard VII

Mathematics

Constructing Perpendicular Bisector of Line Segment

Construct a t...

Question

Construct a triangle $A B C$ such that side $B C = 3.8 m$ , $∠ B = 45^{\circ}$ , and the sides $A B + A C = 6.8 m$ .

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Solution

Step 1: Construct the base $B C = 3.8 m$
Step 2: Construct an angle at B such that ∠B = 45°.

Step 3: Mark a point D on this ray such that BD = AB + AC.

Step 4: Join DC and draw its perpendicular bisector so that it intersects BD at A.

Step 5: Join the points A and C.

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Construct a triangle ABC such that side BC=3.8m, ∠B=45∘, and the sides AB+AC=6.8m.

Step 1: Construct the base BC=3.8m Step 2: Construct an angle at B such that ∠B = 45°. Step 3: Mark a point D on this ray such that BD = AB + AC. Step 4: Join DC and draw its perpendicular bisector so that it intersects BD at A. Step 5: Join the points A and C.

Construct a triangle $A B C$ such that side $B C = 3.8 m$ , $∠ B = 45^{\circ}$ , and the sides $A B + A C = 6.8 m$ .

Step 1: Construct the base $B C = 3.8 m$
Step 2: Construct an angle at B such that ∠B = 45°.

Step 3: Mark a point D on this ray such that BD = AB + AC.

Step 4: Join DC and draw its perpendicular bisector so that it intersects BD at A.

Step 5: Join the points A and C.