Question

Construct a triangle $ABC$ such that side $BC=7m$, $AC–AB=5m$, and $\angle B={45}^{\circ }$ ,such that AB < AC.

Answer 1

Step 1: Construct the base BC = 7cm

Step 2 : Construct an angle at B such that ∠B = 45°.

Step 3: Mark a point D on this ray opposite to ∠B such that BD = AC – AB.

Step 4: Join DC and draw its perpendicular bisector so that it intersects BD at A.

Step 5: Join the points A and C.