Question

Construct a $△ABC$, when $BC=3.6cm,CA=3.0cm$ and $\angle C={30}^{\circ }.$

Answer 1

1. Draw the base side $BC=3.6cm$
2. At point $C$, draw an angle of ${30}^{\circ }$
3. From $C$ cut an arc of length $AC=3.0cm$ using a compass
4. Name the point of intersection of the arm of the angle ${30}^{\circ }$ and the arc drawn in step 3, as $A$
5. Join $A$ to $B$
6. $ABC$ is the required triangle.