Construct a triangle ABC with BC = 7 cm, $∠ B = 60^{\circ}$ and AB = 6 cm. Construct another triangle whose sides are (3/4) times the corresponding sides of $Δ A B C .$

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Solution

Given A $Δ A B C$ with BC = 7 cm, $∠ = 60^{\circ} = a n d$ AB = 6 cm
Steps of Construction:
1. Draw a line segment AB = 6 cm.
2. With B as centre, $∠ B = 60^{\circ}$ .
3. With B as centre and radius BC = 7 cm, draw an arc.
4. Join AC to obtain $Δ A B C$ .
5. Below AB, make an acute angle $∠ B A X$ .
6. Along AX, mark off four points $A_{1}, A_{2}, A_{3} a n d A_{4} s u c h t h a t A A_{1} = A_{1} A_{2} = A_{1} A_{2} = A_{2} A_{3} = A_{3} A_{4} .$
7. Join $A_{4} B .$
8. From $A_{3},$ draw $A_{3} B^{'} / / A_{4} B$
9. From B' draw B'C'// BC
Thus, $Δ A B^{'} C^{'}$ is the required triangle with each of its side (3/4) times the size of the corresponding sides of $Δ A B C$

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Construct a triangle ABC with BC = 7 cm, ∠B=60∘ and AB = 6 cm. Construct another triangle whose sides are (3/4) times the corresponding sides of ΔABC.

Construct a triangle ABC with BC = 7 cm, $∠ B = 60^{\circ}$ and AB = 6 cm. Construct another triangle whose sides are (3/4) times the corresponding sides of $Δ A B C .$