Question

Construct a triangle in which AB = 4 cm, ∠CAB = ${45}^0$ and BC =4 cm. The side length of AC is:

• A. 2.54 cm
• B. 3.54 cm
• C. 5.65 cm
• D. 4.1 cm

Answer 1

The correct option is B 3.54 cm

Given AB = 4 cm, ∠CAB = ${45}^0$ and BC =4 cm.
So, the triangle is isosceles ∠ACB= ∠CAB = ${45}^0$
Therefore the given triangle is isosceles right angle triangle and AC is the hypotenuse.



So, $AC=\sqrt{4^2+4^2}=4\sqrt{2}=5.65$