Construct a triangle of whose side lengths are $4 cm, 5 cm, 7 cm .$

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Solution

To draw the required triangle follow the following steps:-
Draw a line segment $A C = 7 cm .$
With $B$ as center and radius $5 cm,$ draw an arc.
With $A$ as center and radius $4 cm,$ draw another arc cutting the previous arc at $A .$
Join $B C$ and $A C$ .

Therefore, $△ A B C$ is the required triangle.

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Question 99
Draw a triangle whose sides are of lengths 4 cm, 5 cm and 7 cm.

Is it possible to construct a triangle with lengths of its sides as given below? Give reason for your answer.

(i) 5 cm, 4 cm, 9 cm (ii) 8 cm, 7 cm, 4 cm

(iii) 10 cm, 5 cm, 6 cm (iv) 2.5 cm, 5 cm, 7 cm

(v) 3 cm, 4 cm, 8 cm

Q. Draw a triangle whose sides are of lengths 4 cm, 5 cm and 7 cm. Draw the perpendicular bisector of the largest side.

Construct triangle with sides 5 cm, 4 cm, and 6 cm. Then construct another triangle whose sides are $\frac{2}{3}$ times the corresponding sides of triangle

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Construct a triangle of whose side lengths are 4 cm,5 cm,7 cm.

To draw the required triangle follow the following steps:-Draw a line segment AC=7 cm.With B as center and radius 5 cm, draw an arc.With A as center and radius 4 cm, draw another arc cutting the previous arc at A.Join BC and AC.Therefore, △ABC is the required triangle.

Construct a triangle of whose side lengths are $4 cm, 5 cm, 7 cm .$