Question

Construct a $△POQ,$ given $PQ=7cm$ and $\angle PQO={60}^o=\angle OPQ$. Measure the third angle. What type of triangle is this?

Answer 1

In $\Delta OPQ$,

$\begin{array}{c}\angle OPQ+\angle PQO+\angle QOP={180}^0\\ \angle {60}^0+{60}^0+\angle QOP={180}^0\\ \angle QOP={180}^0-{120}^0\\ \angle QOP={60}^0\end{array}$

We get third angles is ${60}^0$ and it is equilateral triangle.