Construct a triangle PQR- given that PQ - 5 cm and - QPR - 60-and - QRP - 45-

Draw a line segment PQ of length 5 nbsp;cm. At P, draw a ray PX by making an angle of 60^∘ nbsp;with PQ (according to nbsp;the given condition, R lies on ...

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Standard VII

Mathematics

Construction of Circumcircle of a Triangle

Construct a t...

Question

Construct a triangle PQR, given that PQ = 5 cm and $∠ Q P R = 60^{\circ}$ and $∠ Q R P = 45^{\circ}$ .

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Solution

Draw a line segment PQ of length 5 cm.

At P, draw a ray PX by making an angle of $60^{\circ}$ with PQ (according to the given condition, R lies on ray PX).

At Q, draw a ray QY by making an angle of $45^{\circ}$ with PQ (according to the given condition, R also lies on ray QY).

The intersection point of ray PX and QY is the point where R lies.

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Similar questions

Q. Construct a triangle PQR, given that PQ = 5 cm and

∠ Q P R = 60^{\circ}

and

∠ Q R P = 45^{\circ}

Q. Construct a

Δ

PQR such that PQ =

6

cm,

∠

QRP =

45^{0}

and angle PQR =

60^{0}

. Locate its incentre and draw its incircle.

Q. Construct a triangle PQR, given that PQ = 5 cm, QR = 8 cm and

∠ P Q R = 45^{\circ}

. [4 MARKS]

Q. Construct

Δ

PQR if PQ

= 5

cm, m

∠

PQR

= 105^{o}

and m

∠

QRP

= 40^{o}

Construct:

$Δ P Q R$ if $P Q = 5 c m$ , $∠ P Q R = 105^{\circ}$ and $∠ Q R P = 40^{\circ}$ .
(Hint : Recall angle-sum property of a triangle),

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Construct a triangle PQR, given that PQ = 5 cm and ∠QPR=60∘and ∠QRP=45∘.

Construct a triangle PQR, given that PQ = 5 cm and $∠ Q P R = 60^{\circ}$ and $∠ Q R P = 45^{\circ}$ .