Question

Construct a triangle PQR, given that PQ = 5 cm and $\angle QPR={60}^{\circ }$and $\angle QRP={45}^{\circ }$. [3 MARKS]

Answer 1

Construction: 1 Mark
Steps: 2 Marks

Draw a line segment PQ of length 5 cm.

At P, draw a ray PX by making an angle of ${60}^{\circ }$ with PQ (according to the given condition, R lies on ray PX).

At Q, draw a ray QY by making an angle of ${45}^{\circ }$ with PQ (according to the given condition, R also lies on ray QY).

The intersection point of ray PX and QY is the point where R lies.