Construct a triangle PQR in which PQ = 4 cm, QR = 4.5 cm and ∠Q = 60°.

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Solution

Steps of construction:

(1) Draw a sufficiently long line segment using a ruler.

(2) Locate points P and Q on it such that PQ = 4 cm.

(3) Construct a sufficiently long line segment QM at Q such that ∠PQR = 60°.

(4) With Q as the centre and radius 4.5 cm, draw an arc cutting QM at R.

(5) Join PR.

Then, PQR is the required triangle.

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Similar questions

Δ P Q R

¯ ¯¯¯¯¯¯ ¯ P Q = 3.5 c m, ¯ ¯¯¯¯¯¯ ¯ P R = 4.5 c m

¯ ¯¯¯¯¯¯¯ ¯ Q R = 5.5 c m

^{\circ}

P Q R S

P Q = 4.5 c m

Q R = 5.2 c m

R S = 5.5 c m

P S = 4 c m

∠ P Q R = 120^{o}

Construct a triangle PQR in which PQ = 4 cm, ∠P = 60° and ∠Q = 60°

P Q R S

P Q = 3.5 c m, Q R = 4.5 c m, R S = 4 c m, ∠ Q = 110^{o}

∠ R = 80^{o}

P Q R S

Q R = 6 c m, P Q = 4 c m

∠ P Q R = 60^{\circ}

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