Question

Construct a triangle $PQR$ in which $QR=6$cm, $\angle Q={60}^{\circ }$ and $PR-PQ=2cm$.

Answer 1

Steps of construction:

$1.$Draw base $QR$ of length $6$cm

$2.$ Now, let's draw $\angle Q={60}^{\circ }$

Let the ray be $QX$

$3.$Open tha compass to length $PR-PQ=2cm$

From point $Q$ as center, cut an arc on ray $QX$ at $Y$

$4.$Join $RY$

$5.$Now, we will draw perpendicular bisector of $RY$

$6.$Mark point $P$ where perpendicular bisector intersects $QX$

$7.$Join $PR$

$\therefore △PQR$ is the required triangle."