Construct a triangle $P Q R$ in which $Q R = 6 c m$ , $∠ Q = 60^{o}$ and $P Q - P O = 2 c m$ .

Open in App

Solution

1. Draw $Q R = 6 c m$
2. Draw angle $60^{\circ}$ at $B$ and cut an arc of $Q O = 2 c m$ .
3. Join $O R$ .
4. Draw a perpendicular bisector of $O R$ which meets $Q O$ at $P .$
5. Join $P - R$ .
$P Q R$ is the required triangle.

Suggest Corrections

Similar questions

P Q R

Q R = 6 c m, ∠ Q = 60^{o}

P R - P Q = 2 c m

P Q R

Q R = 6 c m, ∠ Q = 60^{o} a n d P R - P Q = 2 c m

Q R = 6 c m, ∠ Q = 60^{\circ} a n d P R - P Q = 2 c m

P Q R

∠ Q = 60^{o}

∠ R = 45^{o}

P Q + Q R + P R = 11 c m

Q R = 6 c m, ∠ Q = 60^{\circ} a n d P R - P Q = 2 c m

Join BYJU'S Learning Program