Question

Construct a $△PQR$ such that $\angle P={30}^{\circ },\angle Q={60}^{\circ }$ and $PQ=10cm$.

Type 1 if following are the steps of construction and type 0 if following are not tue steps of construction.

Steps of Construction:

(i) Draw a line segment $PQ=10cm$.

(ii) At $P$, draw a ray making an angle of ${30}^{\circ }$.

(iii) At $Q$, draw another ray making an angle of ${60}^{\circ }$ which intersects the first ray at $R$.

$△PQR$ is the required triangle.

Answer 1

Steps of Construction:

(i) Draw a line segment $PQ=10cm$.

(ii) At $P$, draw a ray making an angle of ${30}^{\circ }$.

(iii) At $Q$, draw another ray making an angle of ${60}^{\circ }$ which intersects the first ray at $R$.

$△PQR$ is the required triangle.

Hence answer will be 1.