You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

Construction of a Triangle with ASA Criterion

Construct a ...

Question

Construct a $△ P Q R$ such that $∠ P = 30^{\circ}, ∠ Q = 60^{\circ}$ and $P Q = 10 c m$ .

If the following are the steps of construction, then answer the following question:

Which of the following is the last step of construction?

Steps of Construction:

Step 1. At $P$ , draw a ray making an angle of $30^{\circ}$ .

Step 2. At $Q$ , draw another ray making an angle of $60^{\circ}$
which intersects the first ray at $R$ .
Thus, $△ P Q R$ is the required triangle.

Step 3. Draw a line segment $P Q = 10 c m$ .

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 2
Steps of Construction:

(i) Draw a line segment $P Q = 10 c m$ .

(ii) At $P$ , draw a ray making an angle of $30^{\circ}$ .

(iii) At $Q$ , draw another ray making an angle of $60^{\circ}$ which intersects the first ray at $R$ .

$△ P Q R$ is the required triangle.

Hence, (B) will be the correct answer.

Suggest Corrections

Similar questions

Construct a

△ P Q R

such that

∠ P = 30^{\circ}, ∠ Q = 60^{\circ}

and

P Q = 10 c m

If following are the steps of construction, then which of the following is not a part of construction?

Steps of Construction:

(i) Draw a line segment

P Q = 10 c m

(ii) At

P

, draw a ray making an angle of

30^{\circ}

(iii) At

Q

, draw another ray making an angle of

60^{\circ}

which intersects the first ray at

R

△ P Q R

is the required triangle.

Q. Vikash followed the following steps to construct a triangle

△

XYZ such that XY = 6 cm,

∠

X = 30

^{\circ}

and

∠

Y = 100

^{\circ}

Step 1:
Draw the line segment XY of length 6 cm.

Step 2:
Draw the ray XP making an angle 30

^{\circ}

at X.

Step 3:
The ray XP and YQ intersects.

Step 4:
Mark the intersecting point as Z.

Step 5:
Join X, Y and Z to get the required

△

XYZ.

Which of the step is missing for constructing this

△

ABC?

Q. To construct a

Δ A B C

in which BC = 5.7 cm,

∠ B = 60^{\circ}

and AB - AC = 3cm, the steps of construction are given below.

Here, AB > AC, i.e. the side containing the base angle B is greater than third side
Steps of construction:
Step 1: Draw the base BC = 5.7 cm and draw a ray BY making an

∠ Y B C = 60^{\circ}

Step 2: Cut the line segment BD = 3 cm from the ray BY.
Step 3 will be

The steps of construction of an isosceles triangle PQR with angle PQR as 110^o are as follows:

(i) Draw the base QR.

(ii) Join P to R to obtain the required triangle PQR.

(iii) At point Q, draw a ray QX making an angle 110° with QR.

(iv) Taking Q as centre, draw an arc of radius equal to PQ. It intersects QX at the point P.

The correct order of steps is

Q. For construction of a

△ P Q R

, where

Q R = 8 c m, P R = 10 c m

and

∠ Q = 90^{\circ}

, its steps for construction is given below in jumbled form. Identify the last step from the following.

Step 1. Draw a line

Q R = 8 c m

Step 2. Join

P

Q

P Q R

is required triangle.

So the first step is

5

Step 3. From

R

cut an arc

P R = 10 c m

using compass.

Step 4. Name the point of intersection of the arm of angle

90^{\circ}

and the arc in step

3

, as

P

Step 5. At point

Q

,draw an angle of

90^{\circ}

Join BYJU'S Learning Program

The correct option is B 2Steps of Construction:(i) Draw a line segment PQ=10 cm.(ii) At P, draw a ray making an angle of 30∘.(iii) At Q, draw another ray making an angle of 60∘ which intersects the first ray at R.△PQR is the required triangle.Hence, (B) will be the correct answer.