Question

Construct a $△$ $PQR$, such that $\angle$ Q=${70}^o$, $\angle R={70}^o$ and $PQ+QR+RP$ $=10$ cm.

Answer 1

Steps of Construction:

1. Draw a line segment AB = 10 cm.( = PQ+QR+RP).

2. At A, construct an angle of 70° and at B, an angle of 70°.

3. Bisect these angles. Let the bisectors of these angles intersect at a point P.

4. Draw perpendicular bisectors DE of AP to intersect AB at Q and FG of PB to intersect AB at R.

5. Join PQ and QR. Then, PQR is the required triangle.