Construct a triangle similar to a given ΔABC such that each of its sides is 23rd of the corresponding side of the ABC It is given that AB = 4 cm, BC = 5 cm and AC = 6 cm
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Solution
Steps of construction : 1 Construct ΔABC where BC = 5 cm, AB = 4 cm and AC = 6 cm 2 Divide the base BC into three equal parts 3 Mark C' on BC such that BC' = 23BC 4 Through C' draw a line parallel to CA intersect AB in A'