wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Construct a triangle whose sides are 3.6cm, 3.0cm and 4.8cm. Bisect the smallest angle and measure each part.


Open in App
Solution

Step 1: Constructing the triangle

Draw a line AB= 4.8cm.

Now, assume a radius of 3.6cm and centre A to draw an arc. And consider the radius of 3.0cm and centre B, draw an arc that intersects our previous arc at C.

Join CA and CB, we get the required triangle ABC.

Step 2: Bisecting the smallest angle

A is the smallest angles because the angle in front of the smallest side is the smallest. So, we will bisect A.

With A as center, draw an arc which cuts AC and AB at point F,E respectively.

With E and F as center, draw arcs which intersect at G.

Draw line AG which passes through D, where D is a point on BC.

Step 3: Measuring each part

Now , we can easily measure each other angle with the help of protractor.

We get, A=40°,B=50°,C=90°


flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
When Two Sides and Their Included Angle Are Given
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon