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Question

Construct a triangle with sides 5 cm, 5.5 cm and 6.5 cm. Now construct another triangle, whose sides are 35 times the corresponding sides of the given triangle. [CBSE 2014]

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Solution

Steps of Construction

Step 1. Draw a line segment QR = 5.5 cm.

Step 2. With Q as centre and radius 5 cm, draw an arc.

Step 3. With R as centre and radius 6.5 cm, draw an arc cutting the previous arc at P.

Step 4. Join PQ and PR. Thus, ∆PQR is the required triangle.

Step 5. Below QR, draw an acute angle RQX.

Step 6. Along QX, mark five points R1, R2, R3, R4 and R5 such that QR1 = R1R2 = R2R3 = R3R4 = R4R5.

Step 7. Join RR5.

Step 8. From R3, draw R3R' || RR5 meeting QR at R'.

Step 9. From R', draw P'R' || PR meeting PQ in P'.



Here, ∆P'QR' is the required triangle, each of whose sides are 35 times the corresponding sides of ∆PQR.

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