Steps of ConstructionStep 1. Draw a line segment QR = 5.5 cm.
Step 2. With Q as centre and radius 5 cm, draw an arc.
Step 3. With R as centre and radius 6.5 cm, draw an arc cutting the previous arc at P.
Step 4. Join PQ and PR. Thus, ∆PQR is the required triangle.
Step 5. Below QR, draw an acute angle
RQX.
Step 6. Along QX, mark five points R
1, R
2, R
3, R
4 and R
5 such that QR
1 = R
1R
2 = R
2R
3 = R
3R
4 = R
4R
5.
Step 7. Join RR
5.
Step 8. From R
3, draw R
3R' || RR
5 meeting QR at R'.
Step 9. From R', draw P'R' || PR meeting PQ in P'.
![](/img/study_content/content_ck_images/images/125711.png)
Here, ∆P'QR' is the required triangle, each of whose sides are
times the corresponding sides of ∆PQR.