Construct a triangle XYZ in which $∠ Y$ = $30^{0}$ , $∠ Z$ = $90^{0}$ and XY + YZ + ZX = 11 cm .

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Solution

Draw a line segment AB of 11 cm
Construct 30° from A and 90° from B
Construct angle bisectors for both the angles
They will meet at X
Draw perpendicular line bisector for AX and BX .
The both lines will meet AB at X and Y
Join XY and XZ
XYZ is our required triangle.

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Similar questions

Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.

X Y Z

∠ Y = 30^{o}, ∠ Z = 90^{o}

X Y + Y Z + Z X = 11 c m

∠ Y = 30^{\circ}, ∠ Z = 90^{\circ} a n d X Y + Y Z + Z X = 11 c m

Construct a triangle XYZ in which $∠ Y = 30^{\circ}, ∠ Z = 90^{\circ} a n d X Y + Y Z + Z X = 11.$

∠ Y = 30^{\circ}, ∠ Z = 90^{\circ} a n d X Y + Y Z + Z X = 11 c m

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